Message3961
Recording a bug to track an issue reported by Shaman Mahmoudi to
jython-users.
From Shaman's email.
http://sourceforge.net/mailarchive/forum.php?thread_name=20769323.post%40talk.nabble.com&forum_name=jython-users
http://www.nabble.com/using-telnetlib-and-its-expect-method-in-jython-td20769323.html#a20769323
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I am using the latest stable version of jython, version 2.2.1 and I am
trying to write a simple telnet program. However, I am having an issue with
the expect method in it.
Here is my code:
import telnetlib
HOST = 'localhost'
user = 'someone'
password = 'someones password'
tn = telnetlib.Telnet(HOST, 22)
aa, bb, cc = tn.expect(['>>>'], 1)
print aa
print bb
print cc
And this is the error message:
Traceback (innermost last):
File "/home/qm/workspace/project000/telnettest.py", line 11, in ?
File "/home/qm/jython/Lib/telnetlib.py", line 623, in expect
File "/home/qm/jython/Lib/select.py", line 204, in
cpython_compatible_select
File "/home/qm/jython/Lib/select.py", line 54, in _getselectable
TypeError: ("Object 'java.nio.channels.SocketChannel[connected
local=/127.0.0.1:45293 remote=/127.0.0.1:22]' is not watchable", 88)
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Date |
User |
Action |
Args |
2008-12-18 17:02:21 | amak | set | recipients:
+ amak |
2008-12-18 17:02:20 | amak | set | messageid: <1229619740.83.0.993882663656.issue1211@psf.upfronthosting.co.za> |
2008-12-18 17:02:20 | amak | link | issue1211 messages |
2008-12-18 17:02:20 | amak | create | |
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