Issue228540
Created on 2001-01-12.11:23:33 by anonymous, last changed 2001-01-12.12:51:54 by pedronis.
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msg253 (view) | Author: Nobody/Anonymous (nobody) | Date: 2001-01-12.11:23:33 | |
In my app I don't use CLASSPATH much 'cause it gonna be somewhat big (about 50 jars) Instead of this I use wildcard as argument to my app-launcher, which parses wildcard and finds every jar i need (builds net of ClassLoaders etc.) and Class.forName("anyClass"); works just fine in any piece of app. Jython package manager(SysPackageManager.java) uses "java.class.path" property alot when huntin' for jars. In my app-launcher expand-java.class.path code was added someth' like that String currPath = System.getProperty("java.class.path"); String separator = ";"; currPath += separator + "myPackage.jar"; System.setProperty("java.class.path", currPath); After that modification alot of *sys-package-mgr*: processing new(modified) jar, 'X:\a\b\c.jar' was shown at the Jython initialization /Py.initPython();/ assuming everithing Ok. BUT! "from a.b.c.d import myClass" - ImportError: cannot import name myClass "from a.b.c.d import *" - Ok "dir()" - names of classes with myClass among... Hm????? "d = new myClass()" - java.lang.NullPointerException at java.lang.Class.isAssignableFrom(Native Method) at org.python.core.PyJavaClass.init__class__(PyJavaClass.java:143) at org.python.core.PyJavaClass.init(PyJavaClass.java:214) at org.python.core.PyJavaClass.initLazy(PyJavaClass.java:78) at org.python.core.PyJavaClass.initialize(PyJavaClass.java:94) at org.python.core.PyJavaClass.initConstructors(PyJavaClass.java:629) at org.python.core.PyJavaClass.__call__(PyJavaClass.java:781) at org.python.core.PyObject.__call__(PyObject.java:260) at org.python.pycode._pyx4.f$0(<console>) at org.python.pycode._pyx4.call_function(<console>) at org.python.core.PyTableCode.call(PyTableCode.java:155) at org.python.core.Py.runCode(Py.java:1050) at org.python.core.Py.exec(Py.java:1071) at org.python.util.PythonInterpreter.exec(PythonInterpreter.java:124) When I put jar containing myClass.class in CLASSPATH explicitly - everithing perfect. Try to put something like String currPath = System.getProperty("java.class.path"); String separator = ";"; currPath += separator + "myPackage.jar"; System.setProperty("java.class.path", currPath); at the beginning of org.python.util.jython and don't put myPackage.jar at CLASSPATH and HAVE FUN ;) andrew@ibis.odessa.ua |
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msg254 (view) | Author: Finn Bock (bckfnn) | Date: 2001-01-12.12:12:17 | |
The "*sys-package-mgr*: processing ..." are done only to support the dir() and "from .. import *" on java packages. The actual loading of the class is performed by a basic Class.forName(..). So it is no surprise that dir() works, but that import doesn't. However, this this more of a feature request than a bug. A task have created to describe the feature: "Loading java classes from other sources" (#24502) The bug report will be closed, but rest assured that the feature is important and that Jython will improve in this area. |
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msg255 (view) | Author: Samuele Pedroni (pedronis) | Date: 2001-01-12.12:51:54 | |
Hi. Maybe this was not clear: clearly the technique does not work in pure java (at least under sun jvm) either. Consider: * M.java public class M { public static void main(String[] args) { String currPath = System.getProperty("java.class.path"); String separator = java.io.File.pathSeparator; currPath += separator + "jar1.jar"; System.out.println(currPath); System.setProperty("java.class.path", currPath); try { Class c = Class.forName("C"); } catch(Throwable e) { System.err.println(e); } } } * C.java (then compiled to C.class, which is put in jar1.jar") public class C {} Running java M one gets: .:jar1.jar java.lang.ClassNotFoundException: C Setting classpath after java init has no effect (!). regards, Samuele Pedroni. |
History | |||
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Date | User | Action | Args |
2001-01-12 11:23:33 | anonymous | create |
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