Message819

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Date	2003-06-26.17:38:08
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Logged In: YES user_id=125722 A workaround is to explicitly construct a java.lang.String: from java.lang import String matches = pattern.split(String("ABCDEFG"))

History
Date	User	Action	Args
2008-02-20 17:17:14	admin	link	issue687826 messages
2008-02-20 17:17:14	admin	create